If you have a large JList
and don't want to scroll through it, it might be a better idea to "paginate" it i.e. display the list in "pages" of a few rows at a time and allow users to flip back and forth between them. To do this, I have written a Java Swing component called PaginatedList
, which looks like this:
You pass in a JList
and specify a page size (the page size is 10 in this example) and it returns a PaginatedList
which you can add onto another JComponent
as normal. The code is shown below:
import java.awt.BorderLayout;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import javax.swing.AbstractAction;
import javax.swing.DefaultListModel;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JList;
import javax.swing.JPanel;
import javax.swing.ListModel;
/**
* A paginated JList. Only displays a specific number of rows
* and allows you to page back and forth through the list.
* with the help of a toolbar.
*/
public class PaginatedList extends JPanel {
private final int pageSize;
private final JList list;
private final ListModel model;
private final int lastPageNum;
private int currPageNum;
private JLabel countLabel ;
private JButton first, prev, next, last;
/**
* @param list the source list
* @param pageSize the number of rows visible
*/
public PaginatedList(JList list, int pageSize) {
super();
this.pageSize = pageSize;
this.list = list;
this.model = list.getModel();
//work out how many pages there are
this.lastPageNum = model.getSize() / pageSize +
(model.getSize() % pageSize != 0 ? 1 : 0);
this.currPageNum = lastPageNum > 0 ? 1 : 0;
setLayout(new BorderLayout());
countLabel = new JLabel() ;
add(countLabel, BorderLayout.NORTH);
add(list, BorderLayout.CENTER);
add(createControls(), BorderLayout.SOUTH);
updatePage();
}
private JPanel createControls() {
first = new JButton(new AbstractAction("<<") {
public void actionPerformed(ActionEvent e) {
currPageNum = 1;
updatePage();
}
});
prev = new JButton(new AbstractAction("<") {
public void actionPerformed(ActionEvent e) {
if (--currPageNum <= 0)
currPageNum = 1;
updatePage();
}
});
next = new JButton(new AbstractAction(">") {
public void actionPerformed(ActionEvent e) {
if (++currPageNum > lastPageNum)
currPageNum = lastPageNum;
updatePage();
}
});
last = new JButton(new AbstractAction(">>") {
public void actionPerformed(ActionEvent e) {
currPageNum = lastPageNum;
updatePage();
}
});
JPanel bar = new JPanel(new GridLayout(1, 4));
bar.add(first);
bar.add(prev);
bar.add(next);
bar.add(last);
return bar;
}
private void updatePage() {
//replace the list's model with a new model containing
//only the entries in the current page.
if(model.getSize() != 0){
final DefaultListModel page = new DefaultListModel();
final int start = (currPageNum - 1) * pageSize;
int end = start + pageSize;
if (end >= model.getSize()) {
end = model.getSize();
}
for (int i = start; i < end; i++) {
page.addElement(model.getElementAt(i));
}
list.setModel(page);
}
//update the label
countLabel.setText("Page " + currPageNum + "/" + lastPageNum);
// update buttons
final boolean canGoBack = currPageNum > 1;
final boolean canGoFwd = currPageNum != lastPageNum;
first.setEnabled(canGoBack);
prev.setEnabled(canGoBack);
next.setEnabled(canGoFwd);
last.setEnabled(canGoFwd);
}
public static void main(String args[]) throws Exception {
// create 100 elements of dummy data.
String[] data = new String[101];
for (int i = 0; i < data.length; i++) {
data[i] = "Item "+ (i + 1);
}
// create a paginated list with page size 20
PaginatedList list = new PaginatedList(new JList(data), 10);
// add it to a frame
JFrame f = new JFrame("Paginated List Demo");
f.add(list);
f.setSize(100, 100);
f.pack();
f.setVisible(true);
}
}
I needed something like this to save time on my coding. Thanks!
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